Getting variable using another variable

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1

Hi,
I’d like to get user password, using other variable - service name.

Example:
#{Name} = “SomeName”
#{SomeName_password} = “SomePassword”

And i want to get #{SomeName_password} , but only specifying in project #{Name} variable, and getting password by convention. But I cannot do something like this: #{#{Name}_password}

As workaround I use password variables with key: User[SomeName].Password, and using in template
#{each user in User}#{if user == Name}#{user.Password}#{/if}#{/each}

Is there maybe a better way?

2

Hi,

Thanks for getting in touch. You’re correct that it’s not possible to substitute a variable within a variable however we do support substitution within an index. For example, if you had variables like the following:

  • MyPassword[Rob] = passwordx
  • MyPassword[Steve] = passwordy
  • MyPassword[Mary] = passwordz

And if you had a variable #{SomeName} = Rob then you could do the following and it will work fine.
#{MyPassword[#{SomeName}]}

This works because we added support to perform variable substitution inside an index as of Octopus 3.3.23 and newer.

The other option is if you defined your variables in a JSON string like the following:
MyPassword = {"Rob": "passwordx", "Steve": "passwordy", "Mary" : "passwordz"} then you do the following and it will work fine as well.
#{MyPassword[#{SomeName}]}

This is available in Octopus 3.5 and newer.

Hope this helps!

Rob

3

The first option is what I need, thanks. It would by nice to add this to documentation. I didn’t even think, that if substitution does not work within variable, it will work with index.

The second option will be troublesome, because of password encryption.

Thanks again.

4

Hi,

Thanks for following-up. I agree that it’s not immediately clear that variable substitution within indexes works. I updated our variable substitution syntax page so this is clearly documented and more easily searchable. Previously, it was only mentioned in a github issue and a blog post.

Thanks again!

Rob